14/9=(2x-8)/(x^2-2x-24)

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Solution for 14/9=(2x-8)/(x^2-2x-24) equation: 



14/9=(2x-8)/(x^2-2x-24)

We move all terms to the left:

14/9-((2x-8)/(x^2-2x-24))=0



Domain of the equation: (x^2-2x-24))!=0

x∈R



We calculate fractions


(-((2x-8)*9)/(9x^2-18x)+(14x^2-28x)/(9x^2-18x)=0



We calculate terms in parentheses: +(-((2x-8)*9)/(9x^2-18x)+(14x^2-28x)/(9x^2-18x), so:

-((2x-8)*9)/(9x^2-18x)+(14x^2-28x)/(9x^2-18x

We calculate fractions


(-((2x-8)*9)*(9x^2-18x)/((9x^2-18x)*(9x^2-18x)+((14x^2-28x)*(9x^2-18x))/((9x^2-18x)*(9x^2-18x)



We calculate terms in parentheses: +(-((2x-8)*9)*(9x^2-18x)/((9x^2-18x)*(9x^2-18x)+((14x^2-28x)*(9x^2-18x))/((9x^2-18x)*(9x^2-18x), so:

-((2x-8)*9)*(9x^2-18x)/((9x^2-18x)*(9x^2-18x)+((14x^2-28x)*(9x^2-18x))/((9x^2-18x)*(9x^2-18x

We can not solve this equation

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